Alumna del CBTa 181
2 semestre grupo "C" Ofimática

jueves, 12 de mayo de 2016

PROBLEMAS DE CONVERSIÓN ; MOLES A GRAMOS

“CONVETIR DE MOLES A GRAMOS”

35 gr de C5H5N
PM= 5(12) + 5(1) + 1(14)= 79g/mol 
N= 35g – 19mol = 0.44mol

28g de N20=
PM= 2(14) + 1(16) + 44g/mol  
N= 28g – 44mol = 0.63mol

25g de Ca3(PO3)3
PM= 3(40) + 9 (30) + 9(16)=534 mol
N= 45g – 534 =0.17

18mol de H2SO4=
PM= 2(1) + (14) + 4(16)= 98g/mol

14mol de c2H3O2Na=
PM= 2(12) + 3(1) + 2(16) + 1(23)= 86
N= 14mol – 86g= 1204


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